20c^2-9cr-18r^2=

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Solution for 20c^2-9cr-18r^2= equation: 


Simplifying
20c2 + -9cr + -18r2 = 0

Reorder the terms:
-9cr + 20c2 + -18r2 = 0

Solving
-9cr + 20c2 + -18r2 = 0

Solving for variable 'c'.

Factor a trinomial.
(5c + -6r)(4c + 3r) = 0


Subproblem 1
Set the factor '(5c + -6r)' equal to zero and attempt to solve:

Simplifying
5c + -6r = 0

Solving
5c + -6r = 0

Move all terms containing c to the left, all other terms to the right.

Add '6r' to each side of the equation.
5c + -6r + 6r = 0 + 6r

Combine like terms: -6r + 6r = 0
5c + 0 = 0 + 6r
5c = 0 + 6r
Remove the zero:
5c = 6r

Divide each side by '5'.
c = 1.2r

Simplifying
c = 1.2r

Subproblem 2
Set the factor '(4c + 3r)' equal to zero and attempt to solve:

Simplifying
4c + 3r = 0

Solving
4c + 3r = 0

Move all terms containing c to the left, all other terms to the right.

Add '-3r' to each side of the equation.
4c + 3r + -3r = 0 + -3r

Combine like terms: 3r + -3r = 0
4c + 0 = 0 + -3r
4c = 0 + -3r
Remove the zero:
4c = -3r

Divide each side by '4'.
c = -0.75r

Simplifying
c = -0.75r
Solution
c = {1.2r, -0.75r}

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